(3/4)(5x-4)=(1/2)(4x+3)

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Solution for (3/4)(5x-4)=(1/2)(4x+3) equation: 



(3/4)(5x-4)=(1/2)(4x+3)

We move all terms to the left:

(3/4)(5x-4)-((1/2)(4x+3))=0



Domain of the equation: 4)(5x-4)!=0

x∈R





Domain of the equation: 2)(4x+3))!=0

x∈R



We add all the numbers together, and all the variables

(+3/4)(5x-4)-((+1/2)(4x+3))=0

We multiply parentheses ..

(+15x^2+3/4*-4)-((+1/2)(4x+3))=0

We calculate fractions


((+15x^2+3*2)(4x+3)))/(-4)*2)(4x+3))+4*)+()/(-4)*2)(4x+3))+4*)=0

We calculate fractions


(((+15x^2+3*2)(4x+3)))*(-4)*2)(4x+3))+4*))/((*(-4)*2)4x)+(-4)*2)(4x+3))+4*)+()*()/((*(-4)*2)4x)=0

We can not solve this equation

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