(3/4)(x+39.99)=20

Solution for (3/4)(x+39.99)=20 equation:

(3/4)(x+39.99)=20

We move all terms to the left:

(3/4)(x+39.99)-(20)=0


Domain of the equation: 4)(x+39.99)!=0

x∈R


We add all the numbers together, and all the variables

(+3/4)(x+39.99)-20=0

We multiply parentheses ..

(+3x^2+3/4*39.99)-20=0

We multiply all the terms by the denominator


(+3x^2+3-20*4*39.99)=0

We get rid of parentheses

3x^2+3-20*4*39.99=0

We add all the numbers together, and all the variables

3x^2-3196.2=0

a = 3; b = 0; c = -3196.2;
Δ = b2-4ac
Δ = 02-4·3·(-3196.2)
Δ = 38354.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{38354.4}}{2*3}=\frac{0-\sqrt{38354.4}}{6}
=-\frac{\sqrt{}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{38354.4}}{2*3}=\frac{0+\sqrt{38354.4}}{6}
=\frac{\sqrt{}}{6}
$