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(3/4)(x+8)=9
We move all terms to the left:
(3/4)(x+8)-(9)=0
Domain of the equation: 4)(x+8)!=0We add all the numbers together, and all the variables
x∈R
(+3/4)(x+8)-9=0
We multiply parentheses ..
(+3x^2+3/4*8)-9=0
We multiply all the terms by the denominator
(+3x^2+3-9*4*8)=0
We get rid of parentheses
3x^2+3-9*4*8=0
We add all the numbers together, and all the variables
3x^2-285=0
a = 3; b = 0; c = -285;
Δ = b2-4ac
Δ = 02-4·3·(-285)
Δ = 3420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3420}=\sqrt{36*95}=\sqrt{36}*\sqrt{95}=6\sqrt{95}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{95}}{2*3}=\frac{0-6\sqrt{95}}{6} =-\frac{6\sqrt{95}}{6} =-\sqrt{95} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{95}}{2*3}=\frac{0+6\sqrt{95}}{6} =\frac{6\sqrt{95}}{6} =\sqrt{95} $
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