(3/4)(x-1)+x=1

Solution for (3/4)(x-1)+x=1 equation:

(3/4)(x-1)+x=1

We move all terms to the left:

(3/4)(x-1)+x-(1)=0


Domain of the equation: 4)(x-1)!=0

x∈R


We add all the numbers together, and all the variables

(+3/4)(x-1)+x-1=0

We add all the numbers together, and all the variables

x+(+3/4)(x-1)-1=0

We multiply parentheses ..

(+3x^2+3/4*-1)+x-1=0

We multiply all the terms by the denominator


(+3x^2+3+x*4*-1)-1*4*-1)=0

We add all the numbers together, and all the variables

(+3x^2+3+x*4*-1)=0

We get rid of parentheses

3x^2+x*4*+3-1=0

We add all the numbers together, and all the variables

3x^2+x*4*+2=0

Wy multiply elements

3x^2+4x^2+2=0

We add all the numbers together, and all the variables

7x^2+2=0

a = 7; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·7·2
Δ = -56
Delta is less than zero, so there is no solution for the equation