(3/4)(x-12)=3

Solution for (3/4)(x-12)=3 equation:

(3/4)(x-12)=3

We move all terms to the left:

(3/4)(x-12)-(3)=0


Domain of the equation: 4)(x-12)!=0

x∈R


We add all the numbers together, and all the variables

(+3/4)(x-12)-3=0

We multiply parentheses ..

(+3x^2+3/4*-12)-3=0

We multiply all the terms by the denominator


(+3x^2+3-3*4*-12)=0

We get rid of parentheses

3x^2+3-12-3*4*=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$