(3/4)(x-4)=5+2x

Solution for (3/4)(x-4)=5+2x equation:

(3/4)(x-4)=5+2x

We move all terms to the left:

(3/4)(x-4)-(5+2x)=0


Domain of the equation: 4)(x-4)!=0

x∈R


We add all the numbers together, and all the variables

(+3/4)(x-4)-(2x+5)=0

We get rid of parentheses

(+3/4)(x-4)-2x-5=0

We multiply parentheses ..

(+3x^2+3/4*-4)-2x-5=0

We multiply all the terms by the denominator


(+3x^2+3-2x*4*-4)-5*4*-4)=0

We add all the numbers together, and all the variables

(+3x^2+3-2x*4*-4)=0

We get rid of parentheses

3x^2-2x*4*+3-4=0

We add all the numbers together, and all the variables

3x^2-2x*4*-1=0

Wy multiply elements

3x^2-8x^2-1=0

We add all the numbers together, and all the variables

-5x^2-1=0

a = -5; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-5)·(-1)
Δ = -20
Delta is less than zero, so there is no solution for the equation