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(3/4)(2x+4)+5=2
We move all terms to the left:
(3/4)(2x+4)+5-(2)=0
Domain of the equation: 4)(2x+4)!=0We add all the numbers together, and all the variables
x∈R
(+3/4)(2x+4)+5-2=0
We add all the numbers together, and all the variables
(+3/4)(2x+4)+3=0
We multiply parentheses ..
(+6x^2+3/4*4)+3=0
We multiply all the terms by the denominator
(+6x^2+3+3*4*4)=0
We get rid of parentheses
6x^2+3+3*4*4=0
We add all the numbers together, and all the variables
6x^2+51=0
a = 6; b = 0; c = +51;
Δ = b2-4ac
Δ = 02-4·6·51
Δ = -1224
Delta is less than zero, so there is no solution for the equation
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