(3/4)a+4=(1/4)*(3a+16)

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Solution for (3/4)a+4=(1/4)*(3a+16) equation: 


a in (-oo:+oo)

(3/4)*a+4 = (1/4)*(3*a+16) // - (1/4)*(3*a+16)

(3/4)*a-((1/4)*(3*a+16))+4 = 0

(-1/4)*(3*a+16)+(3/4)*a+4 = 0

(3*a)/4-1/4*(3*a+16)+4 = 0

(-1/4*4*(3*a+16))/4+(3*a)/4+(4^2)/4 = 0

3*a-1/4*4*(3*a+16)+16 = 0

16-16 = 0

0 = 0

0/4 = 0

0/4 = 0 // * 4

0 = 0

a belongs to the empty set

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