(3/4)b+0.23=0.65

Solution for (3/4)b+0.23=0.65 equation:

(3/4)b+0.23=0.65

We move all terms to the left:

(3/4)b+0.23-(0.65)=0


Domain of the equation: 4)b!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

(+3/4)b+0.23-(0.65)=0

We add all the numbers together, and all the variables

(+3/4)b-0.42=0

We multiply parentheses

3b^2-0.42=0

a = 3; b = 0; c = -0.42;
Δ = b2-4ac
Δ = 02-4·3·(-0.42)
Δ = 5.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{5.04}}{2*3}=\frac{0-\sqrt{5.04}}{6}
=-\frac{\sqrt{}}{6}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{5.04}}{2*3}=\frac{0+\sqrt{5.04}}{6}
=\frac{\sqrt{}}{6}
$