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(3/4)b+4=(2/4)b+10
We move all terms to the left:
(3/4)b+4-((2/4)b+10)=0
Domain of the equation: 4)b!=0
b!=0/1
b!=0
b∈R
Domain of the equation: 4)b+10)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
(+3/4)b-((+2/4)b+10)+4=0
We multiply parentheses
3b^2-((+2/4)b+10)+4=0
We multiply all the terms by the denominator
3b^2*4)b+10)-((+4*4)b+10)+2=0
We add all the numbers together, and all the variables
3b^2*4)b+10)-(16b+10)+2=0
Wy multiply elements
12b^3=0
We do not support ebpression: b^3
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