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(3/4)b-8=(b/4)-3
We move all terms to the left:
(3/4)b-8-((b/4)-3)=0
Domain of the equation: 4)b!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
(+3/4)b-((+b/4)-3)-8=0
We multiply parentheses
3b^2-((+b/4)-3)-8=0
We multiply all the terms by the denominator
3b^2*4)-3)-((+b-8*4)-3)=0
We add all the numbers together, and all the variables
3b^2*4)-3)-((b-32)-3)=0
We add all the numbers together, and all the variables
3b^2*4)-3)-((b=0
Wy multiply elements
12b^3=0
We do not support ebpression: b^3
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