(3/4)k+7=(1/8)k+27

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Solution for (3/4)k+7=(1/8)k+27 equation:



(3/4)k+7=(1/8)k+27
We move all terms to the left:
(3/4)k+7-((1/8)k+27)=0
Domain of the equation: 4)k!=0
k!=0/1
k!=0
k∈R
Domain of the equation: 8)k+27)!=0
k!=0/1
k!=0
k∈R
We add all the numbers together, and all the variables
(+3/4)k-((+1/8)k+27)+7=0
We multiply parentheses
3k^2-((+1/8)k+27)+7=0
We multiply all the terms by the denominator
3k^2*8)k+27)-((+7*8)k+27)+1=0
We add all the numbers together, and all the variables
3k^2*8)k+27)-(56k+27)+1=0
Wy multiply elements
24k^3=0
We do not support ekpression: k^3

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