(3/4)m+5=2

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Solution for (3/4)m+5=2 equation: 



(3/4)m+5=2

We move all terms to the left:

(3/4)m+5-(2)=0



Domain of the equation: 4)m!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

(+3/4)m+5-2=0

We add all the numbers together, and all the variables

(+3/4)m+3=0

We multiply parentheses

3m^2+3=0

a = 3; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·3·3
Δ = -36
Delta is less than zero, so there is no solution for the equation

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