(3/4)m-(1/3)=3.7

Solution for (3/4)m-(1/3)=3.7 equation:

(3/4)m-(1/3)=3.7

We move all terms to the left:

(3/4)m-(1/3)-(3.7)=0


Domain of the equation: 4)m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(+3/4)m-(+1/3)-(3.7)=0

We add all the numbers together, and all the variables

(+3/4)m-3.7-(+1/3)=0

We multiply parentheses

3m^2-3.7-(+1/3)=0

We get rid of parentheses

3m^2-3.7-1/3=0

We multiply all the terms by the denominator


3m^2*3-1-(3.7)*3=0

We add all the numbers together, and all the variables

3m^2*3-12.1=0

Wy multiply elements

9m^2-12.1=0

a = 9; b = 0; c = -12.1;
Δ = b2-4ac
Δ = 02-4·9·(-12.1)
Δ = 435.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{435.6}}{2*9}=\frac{0-\sqrt{435.6}}{18}
=-\frac{\sqrt{}}{18}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{435.6}}{2*9}=\frac{0+\sqrt{435.6}}{18}
=\frac{\sqrt{}}{18}
$