(3/4)n+16=2-(1/8)n

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Solution for (3/4)n+16=2-(1/8)n equation:



(3/4)n+16=2-(1/8)n
We move all terms to the left:
(3/4)n+16-(2-(1/8)n)=0
Domain of the equation: 4)n!=0
n!=0/1
n!=0
n∈R
Domain of the equation: 8)n)!=0
n!=0/1
n!=0
n∈R
We add all the numbers together, and all the variables
(+3/4)n-(2-(+1/8)n)+16=0
We multiply parentheses
3n^2-(2-(+1/8)n)+16=0
We multiply all the terms by the denominator
3n^2*8)n)-(2-(+16*8)n)+1=0
We add all the numbers together, and all the variables
3n^2*8)n)-(2-128n)+1=0
Wy multiply elements
24n^3=0
We do not support enpression: n^3

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