(3/4)x+(1/2)=(7/2)

Solution for (3/4)x+(1/2)=(7/2) equation:

(3/4)x+(1/2)=(7/2)

We move all terms to the left:

(3/4)x+(1/2)-((7/2))=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/4)x+(+1/2)-((+7/2))=0

We multiply parentheses

3x^2+(+1/2)-((+7/2))=0

We get rid of parentheses

3x^2+1/2-((+7/2))=0

We calculate fractions


3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$