(3/4)x+4=7

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Solution for (3/4)x+4=7 equation:



(3/4)x+4=7
We move all terms to the left:
(3/4)x+4-(7)=0
Domain of the equation: 4)x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+3/4)x+4-7=0
We add all the numbers together, and all the variables
(+3/4)x-3=0
We multiply parentheses
3x^2-3=0
a = 3; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·3·(-3)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*3}=\frac{-6}{6} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*3}=\frac{6}{6} =1 $

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