(3/4)x+8=1-x

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Solution for (3/4)x+8=1-x equation: 



(3/4)x+8=1-x

We move all terms to the left:

(3/4)x+8-(1-x)=0



Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/4)x-(-1x+1)+8=0

We multiply parentheses

3x^2-(-1x+1)+8=0

We get rid of parentheses

3x^2+1x-1+8=0

We add all the numbers together, and all the variables

3x^2+x+7=0

a = 3; b = 1; c = +7;
Δ = b2-4ac
Δ = 12-4·3·7
Δ = -83
Delta is less than zero, so there is no solution for the equation

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