(3/4)x-(7/12)x-(2/3)=4

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Solution for (3/4)x-(7/12)x-(2/3)=4 equation: 



(3/4)x-(7/12)x-(2/3)=4

We move all terms to the left:

(3/4)x-(7/12)x-(2/3)-(4)=0



Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 12)x!=0

x!=0/1

x!=0

x∈R



determiningTheFunctionDomain
(3/4)x-(7/12)x-4-(2/3)=0

We add all the numbers together, and all the variables

(+3/4)x-(+7/12)x-4-(+2/3)=0

We multiply parentheses

3x^2-7x^2-4-(+2/3)=0

We get rid of parentheses

3x^2-7x^2-4-2/3=0

We multiply all the terms by the denominator


3x^2*3-7x^2*3-2-4*3=0

We add all the numbers together, and all the variables

3x^2*3-7x^2*3-14=0

Wy multiply elements

9x^2-21x^2-14=0

We add all the numbers together, and all the variables

-12x^2-14=0

a = -12; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·(-12)·(-14)
Δ = -672
Delta is less than zero, so there is no solution for the equation

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