(3/4)x-12=0x=

Solution for (3/4)x-12=0x= equation:

(3/4)x-12=0x=

We move all terms to the left:

(3/4)x-12-(0x)=0


Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/4)x-0x-12=0

We add all the numbers together, and all the variables

-1x+(+3/4)x-12=0

We multiply parentheses

3x^2-1x-12=0

a = 3; b = -1; c = -12;
Δ = b2-4ac
Δ = -12-4·3·(-12)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{145}}{2*3}=\frac{1-\sqrt{145}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{145}}{2*3}=\frac{1+\sqrt{145}}{6}
$