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(3/4)x=123
We move all terms to the left:
(3/4)x-(123)=0
Domain of the equation: 4)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/4)x-123=0
We multiply parentheses
3x^2-123=0
a = 3; b = 0; c = -123;
Δ = b2-4ac
Δ = 02-4·3·(-123)
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{41}}{2*3}=\frac{0-6\sqrt{41}}{6} =-\frac{6\sqrt{41}}{6} =-\sqrt{41} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{41}}{2*3}=\frac{0+6\sqrt{41}}{6} =\frac{6\sqrt{41}}{6} =\sqrt{41} $
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