If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(3/4)x=150
We move all terms to the left:
(3/4)x-(150)=0
Domain of the equation: 4)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/4)x-150=0
We multiply parentheses
3x^2-150=0
a = 3; b = 0; c = -150;
Δ = b2-4ac
Δ = 02-4·3·(-150)
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{2}}{2*3}=\frac{0-30\sqrt{2}}{6} =-\frac{30\sqrt{2}}{6} =-5\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{2}}{2*3}=\frac{0+30\sqrt{2}}{6} =\frac{30\sqrt{2}}{6} =5\sqrt{2} $
| X2+x-20=0 | | 8(x)-5=51 | | 3x−8=−x+4 | | x+7/9=4 | | 4^2+3x=12 | | 10x/3=2x+12 | | 2x=18/x | | (3c+4)(4c-3)=12c²+7c-12 | | 2/3x-6=1/3 | | 8x+1=73# | | 7×p=-56 | | (2x−3)2=4x−6 | | 38-4a=6 | | 25/x/x=1. | | |z|=z+2 | | X3-3x+2=0 | | 5y*0.2=1*1/3*y-0.9 | | 10x-2=-4x+8 | | x^2-5x+6/2x^2-5x+2=0 | | 14j+8=-16j+2 | | (x/2+4)-1=5 | | 18x-(8×-7)=68 | | 5x-26=2x-1 | | |q+2|=9 | | (7/x)+3=x-1 | | 9q2+9q+2=0 | | x^2=19^2+11^2 | | 3x+13=-5x+1 | | 3.6/0.4=x/0.5 | | 1,5x+4=4x-1,4 | | (5(x-3)/2)-1=14 | | 2x-4+2x-4=4x-1 |