(3/4)y+2y=1/2+(4y-3)

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Solution for (3/4)y+2y=1/2+(4y-3) equation: 



(3/4)y+2y=1/2+(4y-3)

We move all terms to the left:

(3/4)y+2y-(1/2+(4y-3))=0



Domain of the equation: 4)y!=0

y!=0/1

y!=0

y∈R





Domain of the equation: 2+(4y-3))!=0

We move all terms containing y to the left, all other terms to the right

(4y-3))!=-2

y∈R



We add all the numbers together, and all the variables

(+3/4)y+2y-(1/2+(4y-3))=0

We add all the numbers together, and all the variables

2y+(+3/4)y-(1/2+(4y-3))=0

We multiply parentheses

3y^2+2y-(1/2+(4y-3))=0

We multiply all the terms by the denominator


3y^2*2+(4y-3))+2y*2+(4y-3))-(1=0

We add all the numbers together, and all the variables

3y^2*2+(4y-3))+2y*2+(4y=0

Wy multiply elements

6y^2+(4y-3))+2y*2+(4y=0

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