(3/4)y+2y=1/2+(4y-3)

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Solution for (3/4)y+2y=1/2+(4y-3) equation:



(3/4)y+2y=1/2+(4y-3)
We move all terms to the left:
(3/4)y+2y-(1/2+(4y-3))=0
Domain of the equation: 4)y!=0
y!=0/1
y!=0
y∈R
Domain of the equation: 2+(4y-3))!=0
We move all terms containing y to the left, all other terms to the right
(4y-3))!=-2
y∈R
We add all the numbers together, and all the variables
(+3/4)y+2y-(1/2+(4y-3))=0
We add all the numbers together, and all the variables
2y+(+3/4)y-(1/2+(4y-3))=0
We multiply parentheses
3y^2+2y-(1/2+(4y-3))=0
We multiply all the terms by the denominator
3y^2*2+(4y-3))+2y*2+(4y-3))-(1=0
We add all the numbers together, and all the variables
3y^2*2+(4y-3))+2y*2+(4y=0
Wy multiply elements
6y^2+(4y-3))+2y*2+(4y=0

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