(3/4)y+2y=1/2+4y-3

Solution for (3/4)y+2y=1/2+4y-3 equation:

(3/4)y+2y=1/2+4y-3

We move all terms to the left:

(3/4)y+2y-(1/2+4y-3)=0


Domain of the equation: 4)y!=0

y!=0/1

y!=0

y∈R



Domain of the equation: 2+4y-3)!=0

We move all terms containing y to the left, all other terms to the right

4y-3)!=-2

y∈R


We add all the numbers together, and all the variables

(+3/4)y+2y-(4y+1/2-3)=0

We add all the numbers together, and all the variables

2y+(+3/4)y-(4y+1/2-3)=0

We multiply parentheses

3y^2+2y-(4y+1/2-3)=0

We get rid of parentheses

3y^2+2y-4y+3-1/2=0

We multiply all the terms by the denominator


3y^2*2+2y*2-4y*2-1+3*2=0

We add all the numbers together, and all the variables

3y^2*2+2y*2-4y*2+5=0

Wy multiply elements

6y^2+4y-8y+5=0

We add all the numbers together, and all the variables

6y^2-4y+5=0

a = 6; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·6·5
Δ = -104
Delta is less than zero, so there is no solution for the equation