(3/4)z+(1/4)z=-4

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Solution for (3/4)z+(1/4)z=-4 equation: 



(3/4)z+(1/4)z=-4

We move all terms to the left:

(3/4)z+(1/4)z-(-4)=0



Domain of the equation: 4)z!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+3/4)z+(+1/4)z-(-4)=0

We add all the numbers together, and all the variables

(+3/4)z+(+1/4)z+4=0

We multiply parentheses

3z^2+z^2+4=0

We add all the numbers together, and all the variables

4z^2+4=0

a = 4; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·4·4
Δ = -64
Delta is less than zero, so there is no solution for the equation

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