(3/49)x+(12/49)=(15/49)

Solution for (3/49)x+(12/49)=(15/49) equation:

(3/49)x+(12/49)=(15/49)

We move all terms to the left:

(3/49)x+(12/49)-((15/49))=0


Domain of the equation: 49)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/49)x+(+12/49)-((+15/49))=0

We multiply parentheses

3x^2+(+12/49)-((+15/49))=0

We get rid of parentheses

3x^2+12/49-((+15/49))=0

We calculate fractions


3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$