(3/4f)+16=2-(1/4f)

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Solution for (3/4f)+16=2-(1/4f) equation: 



(3/4f)+16=2-(1/4f)

We move all terms to the left:

(3/4f)+16-(2-(1/4f))=0



Domain of the equation: 4f)!=0

f!=0/1

f!=0

f∈R





Domain of the equation: 4f))!=0

f!=0/1

f!=0

f∈R



We add all the numbers together, and all the variables

(+3/4f)-(2-(+1/4f))+16=0

We get rid of parentheses

3/4f-(2-(+1/4f))+16=0

We calculate fractions


12f/16f^2+(-(2-(+1*4f)/16f^2+16=0

We calculate fractions

We do not support efpression: f^4

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