(3/4x)+7=(7/12x)+3

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Solution for (3/4x)+7=(7/12x)+3 equation:



(3/4x)+7=(7/12x)+3
We move all terms to the left:
(3/4x)+7-((7/12x)+3)=0
Domain of the equation: 4x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 12x)+3)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+3/4x)-((+7/12x)+3)+7=0
We get rid of parentheses
3/4x-((+7/12x)+3)+7=0
We calculate fractions
36x/48x^2+(-((+7*4x)/48x^2+7=0
We calculate fractions
We do not support expression: x^4

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