(3/4x+30)+(5x-10)+(2/5x+37)=180

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Solution for (3/4x+30)+(5x-10)+(2/5x+37)=180 equation: 



(3/4x+30)+(5x-10)+(2/5x+37)=180

We move all terms to the left:

(3/4x+30)+(5x-10)+(2/5x+37)-(180)=0



Domain of the equation: 4x+30)!=0

x∈R





Domain of the equation: 5x+37)!=0

x∈R



We get rid of parentheses

3/4x+5x+2/5x+30-10+37-180=0

We calculate fractions


5x+15x/20x^2+8x/20x^2+30-10+37-180=0

We add all the numbers together, and all the variables

5x+15x/20x^2+8x/20x^2-123=0

We multiply all the terms by the denominator


5x*20x^2+15x+8x-123*20x^2=0

We add all the numbers together, and all the variables

23x+5x*20x^2-123*20x^2=0

Wy multiply elements

100x^3-2460x^2+23x=0

We do not support expression: x^3

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