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(3/5)(c)=2c-7
We move all terms to the left:
(3/5)(c)-(2c-7)=0
Domain of the equation: 5)c!=0We add all the numbers together, and all the variables
c!=0/1
c!=0
c∈R
(+3/5)c-(2c-7)=0
We multiply parentheses
3c^2-(2c-7)=0
We get rid of parentheses
3c^2-2c+7=0
a = 3; b = -2; c = +7;
Δ = b2-4ac
Δ = -22-4·3·7
Δ = -80
Delta is less than zero, so there is no solution for the equation
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