(3/5)(x-4)=21

Solution for (3/5)(x-4)=21 equation:

(3/5)(x-4)=21

We move all terms to the left:

(3/5)(x-4)-(21)=0


Domain of the equation: 5)(x-4)!=0

x∈R


We add all the numbers together, and all the variables

(+3/5)(x-4)-21=0

We multiply parentheses ..

(+3x^2+3/5*-4)-21=0

We multiply all the terms by the denominator


(+3x^2+3-21*5*-4)=0

We get rid of parentheses

3x^2+3-4-21*5*=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$