(3/5)(x-7)=(7/10)(x+2

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Solution for (3/5)(x-7)=(7/10)(x+2 equation: 



(3/5)(x-7)=(7/10)(x+2

We move all terms to the left:

(3/5)(x-7)-((7/10)(x+2)=0



Domain of the equation: 5)(x-7)!=0

x∈R





Domain of the equation: 10)(x+2)!=0

x∈R



We add all the numbers together, and all the variables

(+3/5)(x-7)-((+7/10)(x+2)=0

We multiply parentheses ..

(+3x^2+3/5*-7)-((+7/10)(x+2)=0

We calculate fractions


((+3x^2+3*10)(x+2))/(-7)*10)(x+2)+5*)+()/(-7)*10)(x+2)+5*)=0

We calculate fractions


(((+3x^2+3*10)(x+2))*(-7)*10)x/((-7)*10)(x*(-7)*10)x-7)*10)x/((-7)*10)(x*(-7)*10)x+2+5*)+()*(=0

We calculate fractions


-7)*10)x+2+5*)+()*(+((((+3x^2+3*10)(x+2))*(-7)*10)x*(()/(((-7)*10)(x*(-7)*10)x*(()+(-7)*10)x*((-7)*10)(x*(-7)*10)x)/(((-7)*10)(x*(-7)*10)x*(()-7)*10)(x*(=0

We can not solve this equation

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