(3/5)*m-(1/2)=(2/3)

Solution for (3/5)*m-(1/2)=(2/3) equation:

(3/5)*m-(1/2)=(2/3)

We move all terms to the left:

(3/5)*m-(1/2)-((2/3))=0


Domain of the equation: 5)*m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(+3/5)*m-(+1/2)-((+2/3))=0

We multiply parentheses

3m^2-(+1/2)-((+2/3))=0

We get rid of parentheses

3m^2-1/2-((+2/3))=0

We calculate fractions


3m^2+()/()+()/()=0

We add all the numbers together, and all the variables

3m^2+2=0

a = 3; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·3·2
Δ = -24
Delta is less than zero, so there is no solution for the equation