(3/5)*p+(1/5)(40-p)=0

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Solution for (3/5)*p+(1/5)(40-p)=0 equation: 



(3/5)*p+(1/5)(40-p)=0



Domain of the equation: 5)*p!=0

p!=0/1

p!=0

p∈R





Domain of the equation: 5)(40-p)!=0

p∈R



We add all the numbers together, and all the variables

(+3/5)*p+(+1/5)(-1p+40)=0

We multiply parentheses

3p^2+(+1/5)(-1p+40)=0

We multiply parentheses ..

3p^2+(-1p^2+1/5*40)=0

We multiply all the terms by the denominator


-1p^2+3p^2*5*40)+(+1=0

Wy multiply elements

-1p^2+600p^3*4+1=0

We do not support eppression: p^3

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