(3/5)+(5m/3)=(44/15)

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Solution for (3/5)+(5m/3)=(44/15) equation:



(3/5)+(5m/3)=(44/15)
We move all terms to the left:
(3/5)+(5m/3)-((44/15))=0
We add all the numbers together, and all the variables
(+5m/3)+(+3/5)-((+44/15))=0
We get rid of parentheses
5m/3+3/5-((+44/15))=0
We calculate fractions
375m^2/()+()/()+()/()=0
We add all the numbers together, and all the variables
375m^2/()+2=0
We multiply all the terms by the denominator
375m^2+2*()=0
We add all the numbers together, and all the variables
375m^2=0
a = 375; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·375·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{750}=0$

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