(3/5)-(1/3x)=(4/9)

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Solution for (3/5)-(1/3x)=(4/9) equation:



(3/5)-(1/3x)=(4/9)
We move all terms to the left:
(3/5)-(1/3x)-((4/9))=0
Domain of the equation: 3x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
-(+1/3x)+(+3/5)-((+4/9))=0
We get rid of parentheses
-1/3x+3/5-((+4/9))=0
We calculate fractions
729x^2/1215x^2+()/1215x^2+(-((+4*3x*5)/1215x^2=0
We multiply all the terms by the denominator
729x^2+(-((+4*3x*5)+()=0
We calculate terms in parentheses: +(-((+4*3x*5)+(), so:
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We calculate terms in parentheses: +(-((+4*3x*5)+(), so:
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We calculate terms in parentheses: +(-((+4*3x*5)+(), so:
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