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(3/5)-(2/5)p=4
We move all terms to the left:
(3/5)-(2/5)p-(4)=0
Domain of the equation: 5)p!=0determiningTheFunctionDomain -(2/5)p-4+(3/5)=0
p!=0/1
p!=0
p∈R
We add all the numbers together, and all the variables
-(+2/5)p-4+(+3/5)=0
We multiply parentheses
-2p^2-4+(+3/5)=0
We get rid of parentheses
-2p^2-4+3/5=0
We multiply all the terms by the denominator
-2p^2*5+3-4*5=0
We add all the numbers together, and all the variables
-2p^2*5-17=0
Wy multiply elements
-10p^2-17=0
a = -10; b = 0; c = -17;
Δ = b2-4ac
Δ = 02-4·(-10)·(-17)
Δ = -680
Delta is less than zero, so there is no solution for the equation
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