(3/5)j-20=9.64

Solution for (3/5)j-20=9.64 equation:

(3/5)j-20=9.64

We move all terms to the left:

(3/5)j-20-(9.64)=0


Domain of the equation: 5)j!=0

j!=0/1

j!=0

j∈R


We add all the numbers together, and all the variables

(+3/5)j-20-(9.64)=0

We add all the numbers together, and all the variables

(+3/5)j-29.64=0

We multiply parentheses

3j^2-29.64=0

a = 3; b = 0; c = -29.64;
Δ = b2-4ac
Δ = 02-4·3·(-29.64)
Δ = 355.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{355.68}}{2*3}=\frac{0-\sqrt{355.68}}{6}
=-\frac{\sqrt{}}{6}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{355.68}}{2*3}=\frac{0+\sqrt{355.68}}{6}
=\frac{\sqrt{}}{6}
$