(3/5)n+15=10+(2/5)n

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Solution for (3/5)n+15=10+(2/5)n equation: 



(3/5)n+15=10+(2/5)n

We move all terms to the left:

(3/5)n+15-(10+(2/5)n)=0



Domain of the equation: 5)n!=0

n!=0/1

n!=0

n∈R





Domain of the equation: 5)n)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+3/5)n-(10+(+2/5)n)+15=0

We multiply parentheses

3n^2-(10+(+2/5)n)+15=0

We multiply all the terms by the denominator


3n^2*5)n)-(10+(+15*5)n)+2=0

We add all the numbers together, and all the variables

3n^2*5)n)-(10+75n)+2=0

Wy multiply elements

15n^3=0

We do not support enpression: n^3

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