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n in (-oo:+oo)
(3/5)*n-10 = (2/5)*n // - (2/5)*n
(3/5)*n-((2/5)*n)-10 = 0
(3/5)*n+(-2/5)*n-10 = 0
1/5*n-10 = 0 // + 10
1/5*n = 10 // : 1/5
n = 10/1/5
n = 50
n = 50
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