(3/5)x+7=13;x=

Solution for (3/5)x+7=13;x= equation:

(3/5)x+7=13x=

We move all terms to the left:

(3/5)x+7-(13x)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/5)x-13x+7=0

We add all the numbers together, and all the variables

-13x+(+3/5)x+7=0

We multiply parentheses

3x^2-13x+7=0

a = 3; b = -13; c = +7;
Δ = b2-4ac
Δ = -132-4·3·7
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{85}}{2*3}=\frac{13-\sqrt{85}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{85}}{2*3}=\frac{13+\sqrt{85}}{6}
$