(3/5)x-15=(6/5)x+12

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Solution for (3/5)x-15=(6/5)x+12 equation: 



(3/5)x-15=(6/5)x+12

We move all terms to the left:

(3/5)x-15-((6/5)x+12)=0



Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5)x+12)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/5)x-((+6/5)x+12)-15=0

We multiply parentheses

3x^2-((+6/5)x+12)-15=0

We multiply all the terms by the denominator


3x^2*5)x+12)-((-15*5)x+12)+6=0

We add all the numbers together, and all the variables

3x^2*5)x+12)-((-75)x+12)+6=0

Wy multiply elements

15x^3-75)x+12)+6=0

We do not support expression: x^3

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