(3/5)y+(2/5)=(4/5)

Solution for (3/5)y+(2/5)=(4/5) equation:

(3/5)y+(2/5)=(4/5)

We move all terms to the left:

(3/5)y+(2/5)-((4/5))=0


Domain of the equation: 5)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+3/5)y+(+2/5)-((+4/5))=0

We multiply parentheses

3y^2+(+2/5)-((+4/5))=0

We get rid of parentheses

3y^2+2/5-((+4/5))=0

We calculate fractions


3y^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{6}=0$