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(3/5)y+2=y
We move all terms to the left:
(3/5)y+2-(y)=0
Domain of the equation: 5)y!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
(+3/5)y-y+2=0
We add all the numbers together, and all the variables
-1y+(+3/5)y+2=0
We multiply parentheses
3y^2-1y+2=0
a = 3; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·3·2
Δ = -23
Delta is less than zero, so there is no solution for the equation
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