(3/5g)-(1/3)=-(10/3)

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Solution for (3/5g)-(1/3)=-(10/3) equation: 



(3/5g)-(1/3)=-(10/3)

We move all terms to the left:

(3/5g)-(1/3)-(-(10/3))=0



Domain of the equation: 5g)!=0

g!=0/1

g!=0

g∈R



We add all the numbers together, and all the variables

(+3/5g)-(+1/3)-(-(+10/3))=0

We get rid of parentheses

3/5g-1/3-(-(+10/3))=0

We calculate fractions


()/135g^2+(-5g)/135g^2+(-(-(+10*5g)/135g^2=0

We multiply all the terms by the denominator


(-5g)+(-(-(+10*5g)+()=0



We calculate terms in parentheses: +(-(-(+10*5g)+(), so:

-(-(+10*5g)+(



We get rid of parentheses

-5g+(-(-(+10*5g)+()=0



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-(-(+10*5g)+(





We calculate terms in parentheses: +(-(-(+10*5g)+(), so:

-(-(+10*5g)+(





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-(-(+10*5g)+(





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-(-(+10*5g)+(





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