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(3/5x(20+30)=15
We move all terms to the left:
(3/5x(20+30)-(15)=0
Domain of the equation: 5x(20+30)-15!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
5x(20+30)!=15
x∈R
(3/5x50-15=0
We multiply all the terms by the denominator
(3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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