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(3/5x)-2=6+(1/4)x
We move all terms to the left:
(3/5x)-2-(6+(1/4)x)=0
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 4)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/5x)-(6+(+1/4)x)-2=0
We get rid of parentheses
3/5x-(6+(+1/4)x)-2=0
We calculate fractions
12x/20x^2+(-(6+(+1*5x)/20x^2-2=0
We calculate fractions
We do not support expression: x^4
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