(3/7)*(x+49)+8=35

Solution for (3/7)*(x+49)+8=35 equation:

(3/7)(x+49)+8=35

We move all terms to the left:

(3/7)(x+49)+8-(35)=0


Domain of the equation: 7)(x+49)!=0

x∈R


We add all the numbers together, and all the variables

(+3/7)(x+49)+8-35=0

We add all the numbers together, and all the variables

(+3/7)(x+49)-27=0

We multiply parentheses ..

(+3x^2+3/7*49)-27=0

We multiply all the terms by the denominator


(+3x^2+3-27*7*49)=0

We get rid of parentheses

3x^2+3-27*7*49=0

We add all the numbers together, and all the variables

3x^2-9258=0

a = 3; b = 0; c = -9258;
Δ = b2-4ac
Δ = 02-4·3·(-9258)
Δ = 111096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{111096}=\sqrt{36*3086}=\sqrt{36}*\sqrt{3086}=6\sqrt{3086}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{3086}}{2*3}=\frac{0-6\sqrt{3086}}{6}
=-\frac{6\sqrt{3086}}{6}
=-\sqrt{3086}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{3086}}{2*3}=\frac{0+6\sqrt{3086}}{6}
=\frac{6\sqrt{3086}}{6}
=\sqrt{3086}
$