(3/7)x+(5/7)=-(4/7)

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Solution for (3/7)x+(5/7)=-(4/7) equation:



(3/7)x+(5/7)=-(4/7)
We move all terms to the left:
(3/7)x+(5/7)-(-(4/7))=0
Domain of the equation: 7)x!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+3/7)x+(+5/7)-(-(+4/7))=0
We multiply parentheses
3x^2+(+5/7)-(-(+4/7))=0
We get rid of parentheses
3x^2+5/7-(-(+4/7))=0
We calculate fractions
3x^2=0
a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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