(3/7)x-(12/5)=(5x+1/2)

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Solution for (3/7)x-(12/5)=(5x+1/2) equation: 



(3/7)x-(12/5)=(5x+1/2)

We move all terms to the left:

(3/7)x-(12/5)-((5x+1/2))=0



Domain of the equation: 7)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/7)x-((+5x+1/2))-(+12/5)=0

We multiply parentheses

3x^2-((+5x+1/2))-(+12/5)=0

We get rid of parentheses

3x^2-((+5x+1/2))-12/5=0

We calculate fractions


3x^2+(-((+5x+1*5)/()+()/()=0



We calculate terms in parentheses: +(-((+5x+1*5)/()+()/(), so:

-((+5x+1*5)/()+()/(

We can not solve this equation

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